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wwwanlingxiao
LeetCodeAnimation
Commits
d2b72e52
Unverified
Commit
d2b72e52
authored
Jul 29, 2020
by
Zong
Committed by
GitHub
Jul 29, 2020
Browse files
Update 0001-Two-Sum.md
多版本代码实现
parent
3daa1877
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0001-Two-Sum/Article/0001-Two-Sum.md
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...
...
@@ -37,7 +37,7 @@

### 代码实现
#### C++
```
// 1. Two Sum
// https://leetcode.com/problems/two-sum/description/
...
...
@@ -62,9 +62,87 @@ public:
};
```
#### C
```
c
// 1. Two Sum
// https://leetcode.com/problems/two-sum/description/
// 时间复杂度:O(n)
// 空间复杂度:O(n)
/**
* Note: The returned array must be malloced, assume caller calls free().
*/
int
*
twoSum
(
int
*
nums
,
int
numsSize
,
int
target
,
int
*
returnSize
){
int
*
ans
=
(
int
*
)
malloc
(
2
*
sizeof
(
int
));
int
i
,
j
;
bool
flag
=
false
;
for
(
i
=
0
;
i
<
numsSize
-
1
;
i
++
)
{
for
(
j
=
i
+
1
;
j
<
numsSize
;
j
++
)
{
if
(
nums
[
i
]
+
nums
[
j
]
==
target
)
{
ans
[
0
]
=
i
;
ans
[
1
]
=
j
;
flag
=
true
;
}
}
}
if
(
flag
){
*
returnSize
=
2
;
}
else
{
*
returnSize
=
0
;
}
return
ans
;
}
```
#### Java
```
// 1. Two Sum
// https://leetcode.com/problems/two-sum/description/
// 时间复杂度:O(n)
// 空间复杂度:O(n)
class Solution {
public int[] twoSum(int[] nums, int target) {
int l = nums.length;
int[] ans=new int[2];
int i,j;
for(i=0;i<l-1;i++)
{
for(j=i+1;j<l;j++)
{
if(nums[i]+nums[j] == target)
{
ans[0]=i;
ans[1]=j;
}
}
}
return ans;
}
}
```
#### Python
```
# 1. Two Sum
# https://leetcode.com/problems/two-sum/description/
# 时间复杂度:O(n)
# 空间复杂度:O(n)
class Solution(object):
def twoSum(self, nums, target):
l = len(nums)
print(nums)
ans=[]
for i in range(l-1):
for j in range(i+1,l):
if nums[i]+nums[j] == target:
ans.append(i)
ans.append(j)
print([i,j])
break
return ans
```

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